One option can beat another in every subgroup and still come out behind once you pool the numbers. It isn't a trick of arithmetic โ it's confoundingA lurking variable tied to both which option each case got and how hard that case was. Pool over it and the comparison is no longer like-for-like.: the option that looks worse per group was simply handed the easier cases. Edit the table and watch the pooled winner flip.
The pooled rate is a size-weighted average, so the mix above is the whole story. When the two options draw from the groups in different proportions โ one loaded with the high-rate group, the other with the low โ pooling stops comparing like with like, and the subgroup winner can lose. Keep the mixes equal and the paradox can't happen.